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Oracle 1Z0-819 Exam covers a wide range of topics related to Java SE 11, including Java basics, Java classes and objects, Java data types, Java operators and expressions, Java control statements, Java inheritance, Java interfaces, Java lambda expressions, Java exception handling, Java I/O streams, Java collections, Java concurrency, and more.

Oracle 1Z0-819 certification exam is designed to test the skills and knowledge of Java developers who work with the Java SE 11 platform. Java SE 11 Developer certification is for developers who want to demonstrate their proficiency in Java programming language and build applications using the latest Java technologies. It is recommended for developers who have experience in Java development and want to advance their career.

Oracle Java SE 11 Developer Sample Questions (Q18-Q23):

NEW QUESTION # 18
Given:

Which code, when inserted at one or more marked positions, would allow classes B and C to compile?

A. public void z() { } // position 3
B. implements A // position 1@Override // position 2
C. @Override // position 3void x () {} // position 3@Override // position 3public void z() { } // position 3
D. @Override // position 2public void z() { } // position 3

Answer: D

NEW QUESTION # 19
Given:

Which is true?

A. The compilation succeeds.
B. The compilation fails due to an error in line 10.
C. The compilation fails due to an error in line 2.
D. The compilation fails due to an error in line 9.
E. The compilation fails due to an error in line 6.
F. The compilation fails due to an error in line 4.
G. The compilation fails due to an error in line 7.

Answer: E

NEW QUESTION # 20
Given the content from the course.txt file:

Which code fragment at line 1 prints the lines that contain Java from the course.txt file?
A)

A. Option C
B. Option B
C. Option D
D. Option E
E. Option A

Answer: B

NEW QUESTION # 21
Given:

What is the result?

A. An exception is thrown at runtime.
B. 42=(x+y)=6
C. 6=(x+y)=6
D. 6=(x+y)=42
E. 42=(x+y)=42

Answer: D

Explanation:

NEW QUESTION # 22
Given the formula to calculate a monthly mortgage payment:

and these declarations:

How can you code the formula?

A. m = p * r * Math.pow(1 + r, n) / Math.pow(1 + r, n) - 1;
B. m = p * (r * Math.pow(1 + r, n) / (Math.pow(1 + r, n) - 1));
C. m = p * (r * Math.pow(1 + r, n) / Math.pow(1 + r, n) - 1);
D. m = p * ((r * Math.pow(1 + r, n) / (Math.pow(1 + r, n)) - 1));

Answer: B

NEW QUESTION # 23
......

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